# Conditional formula for the last copy's length of a component

Hi all,
Can someone tell me is there any way to use a conditional formula for the last copy of a component?
For an example:
if(last copy of a component’s! lenX = 5, then value, else value)

the last copy would be at copy=copies, so

``````lenx =if (copies=copy, remainder, full distance)
``````

If you are working on 2D array:-

based on if being true if >0 or false if<=0, can simplify if(value,1,0)
if copy to be changed at end of row, then take integer from real to see if remainder…

``````lenx =if((copy+1)/num in row-int((copy+1)/num in row), full length, remainder)
``````

so say copies =5, num in rows =, remainder =7, full length =10

then if copy =0,
lenx= 1/3-int(1/3) = 0.333 -0 = 0.333, which is true, so lenx=10

for copy =1
lenx =2/3-int(2/3) = 0.667 -0 = 0.667 which is true, so lenx=10

for copy =2
lenx =3/3-int(3/3) = 1 - 1 =0 which is false, so lenx=7

4/3-1=0.333 true
5/3-1=0.667 true
6/3 -2 =0 false

and so on

1 Like

Is that possible to use same like this to another component?
for an example:
if the component#1 has 5 copies.
I have to use the condition in component#2
if the component#1’s last copy’s length=5, then component#2’s length=10, else value

is this possible?

if allowed component#2 to always be last, then component#1 copies = number - 2
or a condition copies =number-if(remainder,2,1)
component#2 position would be (length of component#1)*(number - 1)

and its length =if(remainder,remainder, 10)
hidden = if(remainder,0,1)