This is totally supported
select u.id, u.username
from users u
where u.email like '%sketchup.com'
Let’s pretend its cpp
select u.id, u.username
from users u
where u.email like '%sketchup.com'
Source:
```
select u.id, u.username
from users u
where u.email like '%sketchup.com'
```
Let's pretend its cpp
```cpp
select u.id, u.username
from users u
where u.email like '%sketchup.com'
```